A charged particle having drift velocity of 7.5×10^(−4) m s^(−1) in an electric field of 3×10^(−10) V m^(−1), has a mobility in m^2 V^(–1) s^(–1) of:

Correct answer: (A) 2.5×10^6. Drift velocity is given by, v_d=E×μ ⇒μ=v_dE=(7.5×10^(−4))/(3×10^(−10)) μ=2.5×10^6 m^2 V^(-1) s^(-1)

Q110 / 180 · NEET 2020 (Phase 1) · Physics

A charged particle having drift velocity of $7.5 \times 10^{- 4} m s^{- 1}$ in an electric field of $3 \times 10^{- 10} V m^{- 1}$ , has a mobility in $m^{2} V^{- 1} s^{- 1}$ of:

Drift velocity is given by, $v_{d} = E \times μ$

$\Rightarrow μ = \frac{v_{d}}{E} = \frac{7 .5 \times 10^{- 4}}{3 \times 10^{- 10}}$

$μ = 2.5 \times 10^{6} m^{2} V^{- 1} s^{- 1}$

Hence, the correct answer is option: 'A'.