Q149 / 180 · AIIMS 2001 · Physics
A charge is placed at the centre of cube of side $a$ then flux linked with one of its given faces will be
- A$\frac{Q}{\varepsilon_0}$
- Correct answerB$\frac{Q}{6 \varepsilon_0}$
- C$\frac{Q}{\varepsilon_0 a^2}$
- D$\frac{Q}{4 \pi \varepsilon_0 a^2}$.
Solution
Gauss's law tells that the total flux through an area enclosing a charge $Q$ is $\frac{Q}{\varepsilon_0}$. Now as the cube is having six faces and as we can assume a symmetrical distribution of fluxes among its faces, the flux associated with one of its faces is $\frac{Q}{6 \varepsilon_0}$.
Hence, the correct answer is option: 'B'.