Q154 / 160 · WBJEE 2015 · Physics
A charge $q$ is placed at one corner of a cube. The electric flux through any of the three faces adjacent to the charge is zero. The flux through any one of the other three faces is
- A$q / 3 \varepsilon_{0}$
- B$q / 6 \varepsilon_{0}$
- C$q / 12 \varepsilon_{0}$
- Correct answerD$q / 24 \varepsilon_{0}$
Solution
Consider the diagram
In above the flux coverage of three face is shown in figure. Which is like a quadrant in any plane. So, flux will be
$$
\phi=\frac{1}{4} \times \frac{q}{6 \varepsilon_{0}}=\frac{q}{24 \varepsilon_{0}}
$$
In above the flux coverage of three face is shown in figure. Which is like a quadrant in any plane. So, flux will be
$$
\phi=\frac{1}{4} \times \frac{q}{6 \varepsilon_{0}}=\frac{q}{24 \varepsilon_{0}}
$$Hence, the correct answer is option: 'D'.