A change of 8.0 mA in the emitter current brings a change of 7.9 mA in the collector current. The values of α and β are

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MARKS Content Team · Accepted Answer

Correct answer: (D) 0.99, 79. Given that, change in emitter current, ∆I_E=8 mA And the change in collector current, ∆I_C=7.9 mA We know that, α=(∆I_C)/(∆I_E)⇒α=7.9/8⇒α≈0.99 Also, we know that β=(α)/(1-α)⇒β=7.9/81-7.9/8 ⇒ β=7.9/(8-7.9)⇒β=7.9/0.1=79 Hence, α=0.99 and β=79

A change of $8.0 mA$ in the emitter current brings a change of $7.9 mA$ in the collector current. The values of $α a n d β$ are

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