A certain metal has a work function of $\Phi =2\mathrm{eV}$. It is irradiated first with $1 \mathrm{W}$ of $400\mathrm{nm}$ light and later with $1 \mathrm{W}$ of $800\mathrm{nm}$ light. Among the following, the correct statement is: [Given:Planck constant $\left(\mathrm{h}\right)$$=6.626\times {10}^{-34} {\mathrm{m}}^2{\mathrm{kgs}}^{-1}$ Speed of light $\left(\mathrm{c}\right)=3\times {10}^8 {\mathrm{ms}}^{-1}$]

• A

  Both colors of light give rise to same number of photoelectrons.
• B

  $400\mathrm{nm}$ light gives rise to less energetic photoelectrons than $800\mathrm{nm}$ light.
• Correct answer
  C

  $400\mathrm{nm}$ light leads to more photoelectrons.
• D

  $800\mathrm{nm}$ light leads to more photoelectrons.

Hence, the correct answer is option: 'C'.