A carrier signal C(t)=25sin2.512×10^10t is amplitude modulated by a message signal m(t)=5sin1.57×10^8t and transmitted through an antenna. What will be the bandwidth of the modulated signal ?

Correct answer: (D) 50MHz. Band width =2f_m ω_m=1.57×10^8=2πf_m BW=2f_m=10^82 Hz=50MHz

Q70 / 90 · JEE Main 2021 (17 Mar Shift 2) · Physics

A carrier signal $C (t) = 25 \sin (2.512 \times 10^{10} t)$ is amplitude modulated by a message signal $m (t) = 5 \sin (1.57 \times 10^{8} t)$ and transmitted through an antenna. What will be the bandwidth of the modulated signal ?

Band width $= 2 f_{m}$

$ω_{m} = 1.57 \times 10^{8} = 2 π f_{m}$

$BW = 2 f_{m} = \frac{10^{8}}{2} Hz = 50 MHz$

Hence, the correct answer is option: 'D'.