Q63 / 120 · NEET 2012 (Mains) · Physics

A car of mass $m$ is moving on a level circular track of radius $R$. If $\mu_s$ represents the static friction between the road and tyres of the car, the maximum speed of the car in circular motion is given by

  • A
    $\sqrt{\mu_s m R g}$
  • B
    $\sqrt{R g / \mu_s}$
  • C
    $\sqrt{m R g / \mu_s}$
  • Correct answer
    D
    $\sqrt{\mu_s R g}$

Solution

In this condition, centripetal force is equal to static frictional force between road and tyres, so $$ \begin{aligned} \mu_s m g & =\frac{m v^2}{R} \\ v_{\max } & =\sqrt{\mu_s R g} \end{aligned} $$

Hence, the correct answer is option: 'D'.

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