Q150 / 180 · COMEDK 2012 · Physics

A capacitor of $10 \mu \mathrm{F}$ is connected to a $10 \mathrm{~V}$ cell. The maximum charge on the capacitor will be

  • A
    $1 \mu \mathrm{C}$
  • B
    $10 \mu C$
  • Correct answer
    C
    $100 \mu \mathrm{C}$
  • D
    $1000 \mu \mathrm{C}$

Solution

Given, $C=10 \mu \mathrm{F}=10 \times 10^{-6} \mathrm{~F}$ $V=10 \mathrm{~V}$ $\begin{aligned} \text{Change,} \quad q &=C \times V=10 \times 10^{-6} \times 10 \\ &=10^{-4} \mathrm{C} \\ &=100 \times 10^{6} \mathrm{C} \\ &=100 \mu \mathrm{C} \end{aligned}$

Hence, the correct answer is option: 'C'.

Relevant Questions