Q138 / 160 · WBJEE 2009 · Physics

A bullet is fired with a velocity u making an angle of $60^{\circ}$ with the horizontal plane. The horizontal component o the velocity of the bullet when it reaches the maximum height is

A
$\mathrm{u}$
B
$0$
C
$\frac{\sqrt{3 u}}{2}$
Correct answer
D
$\frac{\mathrm{u}}{2}$

Solution

Horizontal velocity would be constant so the value of velocity at the highest point will be $u / 2$

Hence, the correct answer is option: 'D'.

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