Q37 / 180 · KCET 2011 · Chemistry
A buffer solution contains $0.1$ mole of sodium acetate dissolved in $1000 \mathrm{~cm}^{3}$ of $0.1 \mathrm{M}$ acetic acid. To the above buffer solution, $0.1$ mole of sodium acetate is further added and dissolved. The $\mathrm{pH}$ of the resulting buffer is
- A$\mathrm{p} K_{a}$
- B$\mathrm{p} K_{a}+2$
- C$\mathrm{p} K_{a}-\log 2$
- Correct answerD$\mathrm{p} K_{a}+\log 2$
Solution
$\mathrm{pH}=\mathrm{p} K_{a}+\log \frac{\text { [salt] }}{\text { [acid] }}$
When extra $0.1$ mole sodium acetate is added
[salt $]=0.2 \mathrm{~mol} \mathrm{dm^{-3 }}$
[acid] $=0.1 \mathrm{~mol} \mathrm{dm}^{-3}$
$\therefore \quad \mathrm{pH}=\mathrm{p} K_{a}+\log \frac{[0.2]}{[0.1]}$
$\mathrm{pH}=\mathrm{p} K_{\mathrm{a}}+\log 2$
Hence, the correct answer is option: 'D'.