Q1 / 120 · VITEEE 2012 · Chemistry

A bubble of air is underwater at temperature $15^{\circ} \mathrm{C}$ and the pressure $1.5$ bar. If the bubble rises to the surface where the temperature is $25^{\circ} \mathrm{C}$ and the pressure is $1.0$ bar, what will happen to the volume of the bubble ?

  • Correct answer
    A
    Volume will become greater by a factor of $1.6$
  • B
    Volume will become greater by a factor of $1.1$
  • C
    Volume will become smaller by a factor of $0.70$
  • D
    Volume will become greater by a factor of $2.9$

Solution

(a) $\because \frac{p_{1} V_{1}}{T_{1}}=\frac{p_{2} V_{2}}{T_{2}}$ (By ideal gas equation) or $\frac{1.5 \times \mathrm{V}_{1}}{288}=\frac{1 \times \mathrm{V}_{2}}{298}$ $\therefore \mathrm{V}_{2}=1.55 \mathrm{~V}_{1}$ i.e, volume of bubble will bealmost $1.6$ times to initial volume of bubble.

Hence, the correct answer is option: 'A'.

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