Q83 / 90 · JEE Main 2021 (17 Mar Shift 2) · Physics

A boy of mass 4 kg is standing on a piece of wood having mass 5 kg. If the coefficient of friction between the wood and the floor is 0.5 , the maximum force that the boy can exert on the rope so that the piece of wood does not move from its place is _______ N. (Round off to the Nearest Integer)

[Take g=10 m s-2

Figure

Correct answer: 30

Solution

Figure

N+T=90

T=μN=0.5(90-T)

1.5T=45

T=30 N

Hence, the correct answer is 30.

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