Q66 / 90 · JEE Main 2024 (06 Apr Shift 2) · Physics
A body of weight $200 \mathrm{~N}$ is suspended from a tree branch through a chain of mass $10 \mathrm{~kg}$. The branch pulls the chain by a force equal to (if $g=10 \mathrm{~m} / \mathrm{s}^2$ ) :
- A$100 \mathrm{~N}$
- B$200 \mathrm{~N}$
- Correct answerC$300 \mathrm{~N}$
- D$150 \mathrm{~N}$
Solution

Chain block system is in equilibrium so $\mathrm{T}=200+100=300 \mathrm{~N} \text {. }$
Hence, the correct answer is option: 'C'.