Q66 / 90 · JEE Main 2024 (06 Apr Shift 2) · Physics

A body of weight $200 \mathrm{~N}$ is suspended from a tree branch through a chain of mass $10 \mathrm{~kg}$. The branch pulls the chain by a force equal to (if $g=10 \mathrm{~m} / \mathrm{s}^2$ ) :

  • A
    $100 \mathrm{~N}$
  • B
    $200 \mathrm{~N}$
  • Correct answer
    C
    $300 \mathrm{~N}$
  • D
    $150 \mathrm{~N}$

Solution

Figure
Chain block system is in equilibrium so $\mathrm{T}=200+100=300 \mathrm{~N} \text {. }$

Hence, the correct answer is option: 'C'.

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