A body of weight 2 kg is suspended as shown in figure. The tension $T_1$ in the horizontal string (in kg-wt) is

• A

  $2 / \sqrt{3}$
• B

  $\sqrt{3} / 2$
• Correct answer
  C

  $2 \sqrt{3}$
• D

  $2$

Solution

$T \sin 30^{\circ}=2 \mathrm{~kg}-\mathrm{wt}$
$\Rightarrow T=4 \mathrm{~kg}-\mathrm{wt}$ $\begin{aligned} T_1 & =T \cos 30^{\circ} \\ & =4 \cos 30^{\circ}=2 \sqrt{3}\end{aligned}$

Hence, the correct answer is option: 'C'.