Q160 / 225 · JEE Main 2005 · Physics

A body $A$ of mass $M$ while falling vertically downwards under gravity breaks into two parts; a body B of mass $1 / 3 \mathrm{M}$ and a body $\mathrm{C}$ of mass $2 / 3 \mathrm{M}$. The centre of mass of bodies $\mathrm{B}$ and $\mathrm{C}$ taken together shifts compared to that of body $\mathrm{A}$ towards

  • A
    depends on height of breaking
  • Correct answer
    B
    does not shift
  • C
    body C
  • D
    body B

Solution

No horizontal external force is acting $$ \begin{aligned} & \therefore \mathrm{a}_{\mathrm{cm}}=0 \\ & \text { since } \mathrm{v}_{\mathrm{cm}}=0 \\ & \therefore \Delta \mathrm{x}_{\mathrm{cm}}=0 \end{aligned} $$

Hence, the correct answer is option: 'B'.

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