Q168 / 225 · JEE Main 2005 · Physics
A body of mass $m$ is accelerated uniformly from rest to a speed $v$ in a time $T$. The instantaneous power delivered to the body as a function time is given by
- Correct answerA$\frac{\mathrm{mv}^2}{\mathrm{~T}^2} \cdot \mathrm{t}$
- B$\frac{m v^2}{T^2} \cdot t^2$
- C$\frac{1}{2} \frac{\mathrm{mv}^2}{\mathrm{~T}^2} \cdot \mathrm{t}$
- D$\frac{1}{2} \frac{\mathrm{mv}^2}{\mathrm{~T}^2} \cdot \mathrm{t}^2$
Solution
$\mathrm{P}=(\mathrm{ma}) \cdot \mathrm{v}$
$=m a^2 t$
$=m \frac{V^2}{T^2} t$
Hence, the correct answer is option: 'A'.