Q168 / 225 · JEE Main 2005 · Physics

A body of mass $m$ is accelerated uniformly from rest to a speed $v$ in a time $T$. The instantaneous power delivered to the body as a function time is given by

  • Correct answer
    A
    $\frac{\mathrm{mv}^2}{\mathrm{~T}^2} \cdot \mathrm{t}$
  • B
    $\frac{m v^2}{T^2} \cdot t^2$
  • C
    $\frac{1}{2} \frac{\mathrm{mv}^2}{\mathrm{~T}^2} \cdot \mathrm{t}$
  • D
    $\frac{1}{2} \frac{\mathrm{mv}^2}{\mathrm{~T}^2} \cdot \mathrm{t}^2$

Solution

$\mathrm{P}=(\mathrm{ma}) \cdot \mathrm{v}$ $=m a^2 t$ $=m \frac{V^2}{T^2} t$

Hence, the correct answer is option: 'A'.

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