A body is whirled in a horizontal circle of radius 25 cm . It has an angular velocity of 13 rad / s . What is its linear velocity at any point on circular path?

Correct answer: (C) 3.25 ~m / s. Given, r =25 ~cm=0.25 ~m ω =13 rad / s ∵ Linear speed = Radius × Angular speed or v =r ω ∴ =0.25 × 13 ⇒ v =3.25 ~m / s

Q91 / 180 · JIPMER 2016 · Physics

A body is whirled in a horizontal circle of radius 25 cm . It has an angular velocity of $13 \mathrm{rad} / \mathrm{s}$. What is its linear velocity at any point on circular path?

A
$2 \mathrm{~m} / \mathrm{s}$
B
$3 \mathrm{~m} / \mathrm{s}$
Correct answer
C
$3.25 \mathrm{~m} / \mathrm{s}$
D
$4.25 \mathrm{~m} / \mathrm{s}$

Solution

Given, $\begin{aligned} r & =25 \mathrm{~cm}=0.25 \mathrm{~m} \\ \omega & =13 \mathrm{rad} / \mathrm{s}\end{aligned}$ $\because$ Linear speed $=$ Radius $\times$ Angular speed $\begin{array}{llrl}\text { or } & & v & =r \omega \\ \therefore & & & =0.25 \times 13 \\ \Rightarrow & & v & =3.25 \mathrm{~m} / \mathrm{s}\end{array}$

Hence, the correct answer is option: 'C'.

A body is whirled in a horizontal circle of radius 25 cm . It has an angular velocity of $13 \mathrm{rad} / \mathrm{s}$. What is its linear velocity at any point on circular path?

Solution

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