Q127 / 160 · AP EAMCET 2019 (21 Apr Shift 2) · Physics

A body is released from a height of 30 m vertically downwards. The speed of the body at which potential energy is twice that of kinetic energy is (Acceleration due to gravity =10 m s-2)

  • A
    202 m s-1
  • Correct answer
    B
    102 m s-1
  • C
    10 m s-1
  • D
    20 m s-1

Solution

Suppose at velocity v,potential energy of body is twice that of kinetic energy.

Using energy conservation-

mgH=KEf+PEf  …1

Since PEf=2×KEf

Put this value in equation 1-

mgH=3×KEf

⇒  mgH=3×12mv2

⇒  v=23gH

⇒  v=102  m s-1 

Hence, the correct answer is option: 'B'.

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