Q126 / 150 · MHT CET 2007 · Physics
A boat at anchor is rocked by waves whose crests are $100 \mathrm{~m}$ apart and velocity is $25 \mathrm{~m} / \mathrm{s}$. The boat bounces up once in every
- A$2500 \mathrm{~s}$
- B$75 \mathrm{~s}$
- Correct answerC$4 \mathrm{~s}$
- D$0.25 \mathrm{~s}$
Solution
Key Idea The distance between the two consecutive crests in transverse wave motion is called wavelength. The boat bounces up, ie, it travels from crest to the consecutive crest along wave motion. Wavelength $=$ distance between two consecutive crests ie,
$$
\lambda=100 \mathrm{~m}
$$
Velocity of wave $=25 \mathrm{~m} / \mathrm{s}$ Hence, time in one bounce of boat
$$
t=\frac{\lambda}{v}=\frac{100}{25}=4 \mathrm{~s}
$$
Hence, the correct answer is option: 'C'.