Q75 / 90 · JEE Main 2022 (29 Jun Shift 2) · Physics

A block of mass 40 kg slides over a surface, when a mass of 4 kg is suspended through an inextensible massless string passing over frictionless pulley as shown below.
The coefficient of kinetic friction between the surface and block is 0.02. The acceleration of block is: (Given g=10 m s-2.)

Figure

  • Correct answer
    A
    811 m s-2
  • B
    1 m s-2
  • C
    15 m s-2
  • D
    45 m s-2

Solution

Figure

For hanging block, 

40-T=4a     ⋯1

Now, maximum value of friction force will be,

fmax=μN=0.02×40×10=8 N

For block on table, T-8=40a     ⋯2

From equation(1) and equation (2), we get32=44a ⇒a=3244=811 m s-2   

Hence, the correct answer is option: 'A'.

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