A block of mass 10 kg, moving in x direction with a constant speed of 10 m s^(-1) , is subjected to a retarding force F=(0.1)x J m^(-1) during its…

Question

A block of mass 10 kg, moving in x direction with a constant speed of 10 m s^(-1) , is subjected to a retarding force F=(0.1)x J m^(-1) during its travel from x=20 m to 30 m . Its final kinetic energy will be:

MARKS Content Team · Accepted Answer

Correct answer: (A) 475 J. m=10 kg, u=10 m s^(-1) Final KE will be given by KE_f=KE_i+W =1/2mu^2+∫2030-0.1xdx =1/2×10×100+-0.1x^222030 =500+(-0.1)/2900-400 KE_f=500+(-0.1500)/2=475 J

A block of mass $10 kg$ , moving in $x$ direction with a constant speed of $10 m s^{- 1}$ , is subjected to a retarding force $F = [(0 .1) x] J m^{- 1}$ during its travel from $x = 20 m$ to $30 m$ . Its final kinetic energy will be:

Solution

Relevant Questions

A block of mass 10 kg, moving in x direction with a constant speed of 10 m s-1 , is subjected to a retarding force F=(0.1)x J m-1 during its travel from x=20 m to 30 m . Its final kinetic energy will be:

Solution

Relevant Questions

A block of mass $10 kg$ , moving in $x$ direction with a constant speed of $10 m s^{- 1}$ , is subjected to a retarding force $F = [(0 .1) x] J m^{- 1}$ during its travel from $x = 20 m$ to $30 m$ . Its final kinetic energy will be: