A black rectangular surface of area A emits energy E per second at 27 °C. If length and breadth are reduced to 13^rd of initial value and temperature…

Question

A black rectangular surface of area A emits energy E per second at 27 °C. If length and breadth are reduced to 13^rd of initial value and temperature is raised to 327 °C, then energy emitted per second becomes

MARKS Content Team · Accepted Answer

Correct answer: (D) 16E/9. E=eσ.AT^4-T04 and A=lb When l and b changes to l/3 and b/3 A→A/9 (E^(′))/E=(A^(′))/A(327+273^4)/(27+273^4) ∴ (E^(′))/E=1/9600^3004 ∴ E^(′)=1/9×2^4×E E^(′)=16E/9

A black rectangular surface of area $A$ emits energy $E$ per second at $27 ° C$ . If length and breadth are reduced to $\frac{1}{3^{rd}}$ of initial value and temperature is raised to $327 ° C$ , then energy emitted per second becomes

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Relevant Questions

A black rectangular surface of area A emits energy E per second at 27 °C. If length and breadth are reduced to 13rd of initial value and temperature is raised to 327 °C, then energy emitted per second becomes

Solution

Relevant Questions

A black rectangular surface of area $A$ emits energy $E$ per second at $27 ° C$ . If length and breadth are reduced to $\frac{1}{3^{rd}}$ of initial value and temperature is raised to $327 ° C$ , then energy emitted per second becomes