A biconvex lens of focal length f_1=10 cm is placed 40 cm in front of a concave mirror of focal length f_2=7.50 cm, as shown in the figure. An object…

Question

A biconvex lens of focal length f_1=10 cm is placed 40 cm in front of a concave mirror of focal length f_2=7.50 cm, as shown in the figure. An object, 2 cm high, is placed 20 cm to the left of the lens. The image formed by the lens, as rays travel to the right, is

MARKS Content Team · Accepted Answer

Correct answer: (C) Real and inverted. From lens equation, 1/v-1/(-20)=1/10 ⇒ v=+20 cm Magnification, m_1=v/u= (+20)/(-20) =-1 Image is real, inverted, and same size as object.

A biconvex lens of focal length $f_{1} = 10 cm$ is placed $40 cm$ in front of a concave mirror of focal length $f_{2} = 7.50 cm,$ as shown in the figure. An object, $2 cm$ high, is placed $20 cm$ to the left of the lens.

The image formed by the lens, as rays travel to the right, is

Solution

More Ray Optics Questions

A biconvex lens of focal length f1=10 cm is placed 40 cm in front of a concave mirror of focal length f2=7.50 cm, as shown in the figure. An object, 2 cm high, is placed 20 cm to the left of the lens. The image formed by the lens, as rays travel to the right, is

Solution

More Ray Optics Questions

A biconvex lens of focal length $f_{1} = 10 cm$ is placed $40 cm$ in front of a concave mirror of focal length $f_{2} = 7.50 cm,$ as shown in the figure. An object, $2 cm$ high, is placed $20 cm$ to the left of the lens.

The image formed by the lens, as rays travel to the right, is