Q69 / 90 · JEE Main 2021 (25 Jul Shift 2) · Physics

A balloon was moving upwards with a uniform velocity of 10 m s-1. An object of finite mass is dropped from the balloon when it was at a height of 75 m from the ground level. The height of the balloon from the ground when object strikes the ground was around: (takes the value of g as 10 m s-2)

  • A
    300 m
  • B
    200 m
  • Correct answer
    C
    125 m
  • D
    250 m

Solution

Figure

Object is projected as shown so as per motion under gravity, 

S=ut+12at2

-75=+10t+12(-10)t2⇒t=5 s

Object takes t=5 s to fall on ground height of balloon from ground, 

H=75+ut

=75+10×5=125 m

Hence, the correct answer is option: 'C'.

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