A ball is thrown vertically. It has a speed of 10 ~m / sec when it has reached one half of its maximum height. How high does the ball rise? Take g=10 ~m / s^2 .

Q105 / 200 · NEET 2005 · Physics

A ball is thrown vertically. It has a speed of $10 \mathrm{~m} / \mathrm{sec}$ when it has reached one half of its maximum height. How high does the ball rise? Take $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$.

Correct answer
A
$10 \mathrm{~m}$
B
$5 \mathrm{~m}$
C
$15 \mathrm{~m}$
D
$20 \mathrm{~m}$

Solution

Using equation of motion $$ V^2=u^2-2 g h $$ After reading max height velocity because zero. $\begin{aligned} 0 & =(10)^2-2 \times 10 \times \frac{1}{2} \\ \Rightarrow \quad h & =\frac{200}{20}=10 \mathrm{~m}\end{aligned}$

Hence, the correct answer is option: 'A'.

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