Q88 / 180 · NEET 2020 (Phase 1) · Physics

A ball is thrown vertically downward with a velocity of $20 m s^{- 1}$ from the top of a tower. It hits the ground after some time with a velocity of $80 m s^{- 1}$ . The height of the tower is: $(g = 10 m s^{- 2})$

A
$340 m$
B
$320 m$
Correct answer
C
$300 m$
D
$360 m$

Solution

We know that,

$v^{2} = u^{2} + 2 g h$
$\Rightarrow 80^{2} = 20^{2} + 2 \times 10 h$
$\Rightarrow h = 300 m$

Hence, the correct answer is option: 'C'.

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