A ball is spun with angular acceleration α=6t^2-2t where t is in second and α is in rad s^(-2). At t=0, the ball has angular velocity of 10 rad s^(-1)…

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A ball is spun with angular acceleration α=6t^2-2t where t is in second and α is in rad s^(-2). At t=0, the ball has angular velocity of 10 rad s^(-1) and angular position of 4 rad. The most appropriate expression for the angular position of the ball is

MARKS Content Team · Accepted Answer

Correct answer: (B) t^42-t^33+10t+4. Given: α=6t^2-2t Using relation α=(dω)/dt=6t^2-2t Integrating the above, ∫10ωdω=∫0t6t^2-2tdt ⇒ω-10=2t^3-t^2 Now, ω=(dθ)/dt=10+2t^3-t^2 ∫4θdθ=∫0t10+2t^3-t^2dt Integrating the above relation, θ-4=10t+t^42-t^33 Thus, angular position of the ball is θ=t^42-t^33+10t+4.

A ball is spun with angular acceleration $α = 6 t^{2} - 2 t$ where $t$ is in second and $α$ is in $rad s^{- 2}$ . At $t = 0$ , the ball has angular velocity of $10 rad s^{- 1}$ and angular position of $4 rad$ . The most appropriate expression for the angular position of the ball is

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Relevant Questions

A ball is spun with angular acceleration α=6t2-2t where t is in second and α is in rad s-2. At t=0, the ball has angular velocity of 10 rad s-1 and angular position of 4 rad. The most appropriate expression for the angular position of the ball is

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Relevant Questions

A ball is spun with angular acceleration $α = 6 t^{2} - 2 t$ where $t$ is in second and $α$ is in $rad s^{- 2}$ . At $t = 0$ , the ball has angular velocity of $10 rad s^{- 1}$ and angular position of $4 rad$ . The most appropriate expression for the angular position of the ball is