Q77 / 160 · TS EAMCET 2023 (13 May Shift 2) · Mathematics
A bag contains 3 red, 5 black and 7 blue balls. If three balls are drawn at random simultaneously from the bag then the probability of getting at least two blue balls is
- Correct answerA$\frac{29}{65}$
- B$\frac{29}{130}$
- C$\frac{9}{65}$
- D$\frac{9}{130}$
Solution
Atleast 2 blue $=$ ( 2 blue and 1 other) or ( 3 blue)
$$
\begin{aligned}
& P \text { (atleast 2 blue) }=\frac{{ }^7 C_2 \times{ }^8 C_1}{{ }^{15} C_3}+\frac{{ }^7 C_3}{{ }^{15} C_3} \\
& =\frac{{ }^7 C_2 \times{ }^8 C_1+{ }^7 C_3}{{ }^{15} C_3} \\
& =\frac{168+35}{7 \times 5 \times 13}=\frac{29}{65} .
\end{aligned}
$$
Hence, the correct answer is option: 'A'.