Q17 / 237 · NTA Abhyas (NEET) 2020 · Physics · Semiconductors

$\bar{A \cdot \bar{B} + \bar{A} \cdot B}$ is equivalent to

A
$A \cdot \bar{B} + \bar{A} \cdot B$
Correct answer
B
$(A + \bar{B}) + (\bar{A} + B)$
C
$\bar{A \cdot \bar{B} + \bar{A} \cdot B}$
D
$(A + B) \cdot (\bar{A} + B)$

Solution

\bar{A \cdot \bar{B} + \bar{A} \cdot B}

\bar{A \cdot \bar{B}} . \bar{\bar{A} \cdot B}

(\bar{A} + \bar{B}) . (\bar{A} + \bar{B})

(\bar{A} + B) . (A + \bar{B})

Hence, the correct answer is option: 'B'.

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