Q23 / 90 · JEE Main 2021 (16 Mar Shift 2) · Chemistry

A and B decompose via first order kinetics with half-lives 54.0 min and 18.0 min respectively. Starting from an equimolar non-reactive mixture of A and B, the time taken for the concentration of A to become 16 times that of B is ______ min. (Round off to the Nearest Integer).

Correct answer: 108

Solution

Given A=t1/2=54 min

B=t1/2=18 min

t=0 'x' M     t=0 'x' M

⇒ To calculate : At=16×Bt time =?

⇒ For I order kinetic : At=A02n

n→ no. of Half lives

⇒ Now from the relation (1)

⇒x2n1=x2n2×16⇒2n2=2n1×24

⇒n2=n1+4⇒tt1/22=tt1/21+4

⇒t118-154=4⇒t=4×18×5436

⇒t=108 min

Hence, the correct answer is 108.

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