Q59 / 75 · JEE Main 2025 (28 Jan Shift 2) · Physics
A 400 g solid cube having an edge of length 10 cm floats in water. How much volume of the cube is outside the water ?
(Given : density of water $=1000 \mathrm{~kg} \mathrm{~m}^{-3}$ )
- A$1400 \mathrm{~cm}^3$
- Correct answerB$600 \mathrm{~cm}^3$
- C$4000 \mathrm{~cm}^3$
- D$400 \mathrm{~cm}^3$
Solution
Volume of cube inside water
$\begin{aligned}
& =\left(\frac{\text { Denslty of cube }}{\text { Denslty of water }}\right) \times \text { Volume of cube } \\
& =\frac{\text { Mass of cube }}{\text { Denslty of water }} \\
& =\frac{400 \mathrm{gm}}{1 \mathrm{gm} / \mathrm{cm}^3} \\
& =400 \mathrm{~cm}^3
\end{aligned}$
Volume of cube outside water
$\begin{aligned}
& =\text { Volume of cube }- \text { Volume of cube inside water } \\
& =1000 \mathrm{~cm}^3-400 \mathrm{~cm}^3 \\
& =600 \mathrm{~cm}^3
\end{aligned}$
Hence, the correct answer is option: 'B'.