Q87 / 90 · JEE Main 2023 (15 Apr Shift 1) · Physics

A 20 cm long metallic rod is rotated with 210 rpm about an axis normal to the rod passing through its one end. The other end of the rod is in contact with a circular metallic ring. A constant and uniform magnetic field 0.2 T parallel to the axis exists everywhere. The emf developed between the centre and the ring is _________mV.

(Take π=227)

Correct answer: 88

Solution

The data given is 

ω=210×2π60 rad s-1=7π  rad s-1l=0.2 mB=0.2 T

The emf is given by

ε=Bωl22

=0.2×7π×0.222

=88 mV

Hence, the correct answer is 88.

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