Q77 / 160 · WBJEE 2011 · Mathematics

\(\int \frac{\sin ^8 x-\cos ^8 x}{1-2 \sin ^2 x \cos ^2 x} d x\)

  • Correct answer
    A
    \(-\frac{1}{2} \sin 2 x+C\)
  • B
    \(\frac{1}{2} \sin 2 \mathrm{x}+\mathrm{C}\)
  • C
    \(\frac{1}{2} \sin x+C\)
  • D
    \(-\frac{1}{2} \sin x+C\)

Solution

Hints: \(\int\left(\sin ^2 x-\cos ^2 x\right) d x=-\int \cos ^{2 x} d x=-\frac{1}{2} \sin 2 x+C\)

Hence, the correct answer is option: 'A'.

Relevant Questions