Q12 / 100 · BITSAT 2024 (Memory Based Paper 3) · Chemistry

58.5 g of NaCl and 180 g of glucose were separately dissolved in 1000 mL of water. Identify the correct statement regarding the elevation of boiling point of the resulting solution.

  • Correct answer
    A
    NaCl solution will show higher elevation of boiling point.
  • B
    Glucose solution will show higher elevation of boiling point.
  • C
    Both the solution will show equal elevation of boiling point.
  • D
    None will show boiling point elevation.

Solution

$\begin{aligned} \text { } 58.5 \mathrm{~g} \mathrm{NaCl} & =\frac{58.5}{58.5} \mathrm{~mol} \\ & =1 \mathrm{~mol} \\ 180 \mathrm{~g} \text { of glucose } & =\frac{180}{180}=1 \mathrm{~mol} \end{aligned}$ Thus, we have 1 M NaCl and 1 M glucose solution. But NaCl dissociates in the solution and glucose does not dissociates. Thus particle concentration is more in NaCl . Hence, NaCl solution will have higher elevation in boiling point.

Hence, the correct answer is option: 'A'.

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