$500 \mathrm{g}$ of water is heated from $30°\mathrm{C}$ to $90°\mathrm{C}.$ What is the change in its internal energy? (Specific heat of water is $4184 \mathrm{J}{ \mathrm{kg}}^{-1}{ \mathrm{K}}^{-1}$)

• Correct answer
  A

  $1.25\times {10}^5 \mathrm{J}$
• B

  $2.0\times {10}^5 \mathrm{J}$
• C

  $1.3\times {10}^4 \mathrm{J}$
• D

  $2.0\times {10}^4 \mathrm{J}$

Hence, the correct answer is option: 'A'.