Q24 / 155 · WBJEE 2023 · Chemistry

\(4 f^2\) electronic configuration is found in

  • A
    \(\mathrm{Pr}\)
  • Correct answer
    B
    \(\mathrm{Pr}^{3+}\)
  • C
    \(\mathrm{Nd}^{3+}\)
  • D
    \(\mathrm{Pm}^{3+}\)

Solution

Hint : \(\operatorname{Pr}(59)=[X e] 4 f^3 6 s^2\) \(\therefore \mathrm{Pr}^{+3}=[\mathrm{Xe}] 4 \mathrm{f}^2\)

Hence, the correct answer is option: 'B'.

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