Q81 / 160 · WBJEE 2011 · Mathematics

4 boys and 2 girls occupy seats in a row at random. Then the probability that the two girls occupy seats side by side is

A
\(\frac{1}{2}\)
B
\(\frac{1}{4}\)
Correct answer
C
\(\frac{1}{3}\)
D
\(\frac{1}{6}\)

Solution

\(\begin{gathered} \text {Hints: } \mathrm{n}(\mathrm{e})=\lfloor 5 \cdot\lfloor 2 \\ \mathrm{n}(\mathrm{s})=\lfloor 6 \\ \mathrm{p}=\frac{\lfloor 5 \cdot \lfloor 2}{\lfloor 6}=\frac{2}{6}=\frac{1}{3} \end{gathered}\)

Hence, the correct answer is option: 'C'.

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