Q107 / 270 · NDA 2019 (Phase 2) · General Ability

10 g of ice at $-10^{\circ} \mathrm{C}$ is mixed with 10 g of water at $0^{\circ} \mathrm{C}$. The amount of heat required to raise the temperature of mixture to $10^{\circ} \mathrm{C}$ is

  • A
    400 cal
  • B
    550 cal
  • Correct answer
    C
    1050 cal
  • D
    1200 cal

Solution

Heat required for raising the temperature of water $\theta \mathrm{w}=$ $\mathrm{mw} \mathrm{cw} \mathrm{Tw}=418.6 \mathrm{~J}$, Similarly, heat required for raising the temperature of ice $\theta \mathrm{i}=4381.2 \mathrm{~J}$, thus the total heat in calorie will be roughly 1050 calorie.

Hence, the correct answer is option: 'C'.

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