1 mole of FeSO_4 (atomic weight of Fe is 55.84 g mol^(−1) ) is oxidized to Fe_2(SO_4)_3 . Calculate the equivalent weight of ferrous ion

Question

1 mole of FeSO_4 (atomic weight of Fe is 55.84 g mol^(−1) ) is oxidized to Fe_2(SO_4)_3 . Calculate the equivalent weight of ferrous ion.

MARKS Content Team · Accepted Answer

Correct answer: (A) 55.84. 2 Fe +2 SO_4 →2 Fe_2 +3 (SO_4 ) 3 Change in oxidation state per Fe atom is 1. So, equivalent weight = atomic weight.

1 mole of $F e S O_{4}$ (atomic weight of $Fe$ is $55 .84 g {mol}^{- 1}$ ) is oxidized to $F e_{2} (S O_{4})_{3}$ . Calculate the equivalent weight of ferrous ion.