Q23 / 160 · TS EAMCET 2024 (11 May Shift 1) · Chemistry

0.592 g of copper is deposited in 60 minutes by passing 0.5 amperes current through a solution of copper (II) sulphate. The electro chemical equivalent of copper (II) (in $\mathrm{g} \mathrm{C}^{-1}$ ) is $\left(\mathrm{F}=96500 \mathrm{C} \mathrm{mol}^{-1}\right)$

  • A
    $3.3 \times 10^{-3}$
  • Correct answer
    B
    $3.3 \times 10^{-4}$
  • C
    $6.6 \times 10^{-3}$
  • D
    $6.6 \times 10^{-4}$

Solution

$\begin{aligned} & \text { According to Faraday law, } \\ & \mathrm{W}=\mathrm{Zit} \\ & \mathrm{Z}=\text { electro chemical equivalent } \\ & \text { given, } \\ & \mathrm{W}=0.592 \mathrm{~g} \\ & \mathrm{t}=60 \text { minutes } \\ & =60 \times 60 \mathrm{~s} \\ & =3600 \mathrm{~s} \\ & \mathrm{i}=0.5 \mathrm{~A} \\ & \therefore \quad 0.592=\mathrm{Z} \times 0.5 \times 3600 \\ & \mathrm{Z}=3.3 \times 10^{-4} \mathrm{~g} \mathrm{C}^{-1}\end{aligned}$

Hence, the correct answer is option: 'B'.

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