Q28 / 180 · KCET 2024 · Chemistry

0.48 g of an organic compound on complete combustion produced 0.22 g of $\mathrm{CO}_2$. The percentage of C in the given organic compound is

  • A
    $25$
  • B
    $50$
  • Correct answer
    C
    $12.5$
  • D
    $87.5$

Solution

Given, Mass of organic compound $=0.48 \mathrm{~g}$ Mass of $\mathrm{CO}_2$ produced $=0.22 \mathrm{~g}$ \% C =? Using formula $\% \mathrm{C}=\frac{12}{44} \times \frac{\text { mass of } \mathrm{CO}_2}{\text { mass of organic compound }} \times 100$ $=\frac{12}{44} \times \frac{0.22}{0.48} \times 100$ $=12.5 \%$

Hence, the correct answer is option: 'C'.

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