0.01MKMnO_4 solution was added to 20.0 mL of 0.05M Mohr 's salt solution through a burette. The initial reading of 50 mL burette is zero. The volume…

Question

0.01MKMnO_4 solution was added to 20.0 mL of 0.05M Mohr 's salt solution through a burette. The initial reading of 50 mL burette is zero. The volume of KMnO_4 solution left in the burette after the end point is....... mL. (nearest integer)

MARKS Content Team · Accepted Answer

Correct answer: 30. Fe^(2+)+MnO4-⟶Fe^(3+)+Mn^(2+) vf=1 vf=5 vf=Valency factor Milli equivalents of mohr's salt = milli equivalents of KMnO_4 1×0.05×20=5 0.01×V_ml Vml =20ml Volume of KMnO_4 left = 50-20=30ml

$0.01 {MKMnO}_{4}$ solution was added to $20.0 mL$ of $0.05 M Mohr$ 's salt solution through a burette. The initial reading of $50 mL$ burette is zero. The volume of ${KMnO}_{4}$ solution left in the burette after the end point is....... $mL$ . (nearest integer)

Solution

Relevant Questions

0.01MKMnO4 solution was added to 20.0 mL of 0.05M Mohr 's salt solution through a burette. The initial reading of 50 mL burette is zero. The volume of KMnO4 solution left in the burette after the end point is....... mL. (nearest integer)

Solution

Relevant Questions

$0.01 {MKMnO}_{4}$ solution was added to $20.0 mL$ of $0.05 M Mohr$ 's salt solution through a burette. The initial reading of $50 mL$ burette is zero. The volume of ${KMnO}_{4}$ solution left in the burette after the end point is....... $mL$ . (nearest integer)